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Neco 2016 practical physics answers
PracticalPhysicsQuestions & Answers.
1a)
Lo=125.00cm^3
Diameter of measuring cylinder=3.21cm^3
S/N:1,2,3,4,5
m(g):50.0,100.0,150.0,200.0,250.0
Lo(cm^3):125.0,125.0,125.0,125.0,125.0
L(cm? 3):135.0,145.0,165.0,185.0,205.0
y=L-Lo(cm^3):10.0,20.0,40.0,60.0,80.0
V=0.785d^2y:80.89,161.77,323.55,485.32,647.10
1aviii)
Slope=(250.0-150.0)/(647.10-323.55)
=100.0/323.55
=0.309
1aix)
-I ensured that parallax error is avoided
-I ensured that mass is gently inserted into the cylinder to avoid spillage
1b)
Archimede's principle stste that when a body is partially or wholly immersed into a fluid it experiences an upthrust which is equal to weight of the body
1bii)
volume of the wood = 2.0 × 10^-5m^3
mass = 5.0 × 10^-3kg
g = 10.0ms^-2
density of water = 1.0 × 10^3kgm^-3
volume of object = mass/density
density = mass/volume
density of the object = mass of the object/volume
= 5.0×10^-3/2.0×10^-5
= 2.5×10^2kgm^3
upthrust = volume 0f the object × density of liquid × g
=2.0×10^-5 × 1.5×10^2×10
= 0.3N
3) TABULATE READINGS
R(N) - |2.00| |4.00| |6.00| |8.00| |10.00|
1(A) - |2.85| |2.21| |2.00| |1.75| |1.65|
R^-1 - |0.5| |0.25| |0.17| |0.13| |0.10|
i)i ensure zero error in the terminal used
ii) i ensure clean terminals
iii)i ensure all wires are tightened together
3b) Ohm's law states that current flow through a conductivity wire is directly proportional to its potential difference applied across its end provided that temperature remain constant
Revisit after 40 seconds for Answers
Alternative 2
1)
S/N - |1|2|3|4|5|
M(g) - |50.0|100.0|150.0|200.0|250.0|
Lv(cm) - |50.0|50.0|50.0|50.0|50.0|
L1(cm) - |60.0|70.0|80.0|90.0|100.0|
y=Le-v(cm^3) - |10.00|20.00|30.00|40.00|50.00|
1aix)
i. i avoided error due to parallel
ii. i ensured that the mass is gently dropped into the liquid
(1bi)
Archimedes principle states that when a body is wholly or partly immersed in a liquid the weight of the body is equal to the mass of the fluid displaced
1bii)
volume of the wood = 2.0 × 10^-5m^3
mass = 5.0 × 10^-3kg
g = 10.0ms^-2
density of water = 1.0 × 10^3kgm^-3
volume of object = mass/density
density = mass/volume
density of the object = mass of the object/volume
= 5.0×10^-3/2.0×10^-5
= 2.5×10^2kgm^3
upthrust = volume 0f the object × density of liquid × g
=2.0×10^-5 × 1.5×10^2×10
= 0.3N
===============================
CLICK HERE FOR NUMBER 3 GRAPH
3)
TABULATE READINGS
R(N) - |2.00| |4.00| |6.00| |8.00| |10.00|
1(A) - |2.85| |2.21| |2.00| |1.75| |1.65|
R^-1 - |0.5| |0.25| |0.17| |0.13| |0.10|
PRECAUTIONS
i)i ensured clean terminals
ii)i avioved zero error on the ammeter used
iii)i ensured tight connection of all wires
3b)
ohm's law states that the current flowing through a metallic conductor is proportional to its portential difference provided that physical condition is constant i.e V x I
(3 bii )
E & L
E =kL
E / L = k
E 1 / L 1 =E 2 / L 2
l 2 =E 2 L 1 / E 1 =(1 .5 * 1 )/ 2 . 5
L 2 =0 .6 cm
the new balance point when 1 .5 v cell is connected across it is 0 .6 cm
3c)
slope(s) = DR^-1/DI = 0.25-0.10/2.21-1.65
=0.15/0.56
slope(s)=0.27
intercept c = -0.35
evaluation
1/5=1/0.27=3.70
evalution
1/C = 1/-0.35
=-2.86
Created at 2016-06-07
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